In a crucial divisional matchup last Sunday, the Jacksonville Jaguars emerged victorious with a narrow 24-21 win over the Houston Texans. The standout of the game was none other than edge rusher Josh Allen, whose impressive performance played a significant role in securing the victory for his team.

Allen made his presence felt throughout the game, sacking Texans quarterback C.J. Stroud a staggering 2.5 times. His relentless pressure on Stroud proved to be a major factor in disrupting the Houston offense, especially during the crucial moments of the game. Notably, two of Allen's sacks came on Houston's final drive, pushing them back and adding lost yardage to their total. This ultimately forced the Texans to attempt a challenging 58-yard field goal on the game's final play, which struck the crossbar, leaving them with a heartbreaking loss.

Recognizing Allen's outstanding performance, the NFL announced that he has been named the AFC Defensive Player of the Week. This prestigious honor marks the third time in the past three seasons that Allen has received this recognition, highlighting his consistency and impact on the field.

With this latest achievement, Allen's numbers continue to impress. He now boasts a career-high 12 sacks on the season, establishing himself as a formidable force within the league. As his current contract nears its end in 2023, Allen's exceptional performance positions him for a potentially lucrative second contract, solidifying his status as a valuable asset for the Jaguars.

As the Jacksonville Jaguars strive to maintain their lead in the AFC South, Josh Allen's dominant showcase against the Texans serves as a testament to his exceptional skills as an edge rusher. With his relentless pursuit of opposing quarterbacks, Allen has not only helped secure victories for his team but has also solidified his position as one of the league's premier defensive players.